Dear Dr. Jonkman,
I am applying the Torque vs GenSpeed Curve in the Torque Control Loop inside Simulink for simulating the NREL 5MW wind turbine with FAST v8 (v8.16.00a-bjj, 27-Jul-2016).
I have defined the curve with a MATLAB Function block, basing on the information given in the “Definition of a 5-MW Reference Wind Turbine for Offshore System Development” document (https://www.nrel.gov/docs/fy09osti/38060.pdf) in pages 19-20.
Nevetherless, I have some doubts about some of the points defining the curve, which I would like to clarify. I know this issue has been trated previously, but I was not able to understand fully. I attach an image of the curve for referring to the specific points which I would like to define.
As I understand, the transitional generator speed between Regions 2 1/2 and 3 is the 99% of the rated, therefore:
wGen_A = wGenRated * 0.99 = 1173.7 * 0.99 = 1161.963 rpm
From that point, until the cut off wind speed (in Region 3), the power is held constant, and therefore as I understand, in point A we have already reached the rated power (5MW).
Taking that consideration into account, my calculations for the torque in that point give the following result:
torque_A(Nm) = GenPwrRatedMec(W) / wGen_A(rad/s) = (GenPwrNom(W) / GenEff) / wGen_A(rad/s) = 5e6 / 0.944 / (1161.963 * pi / 30) = 43528.84 Nm
Therefore, the torque obtained in point A is higher than the rated torque (43093.55Nm), which is reached later, with the rated wind speed.
As for point B, I calculated it as the crossing point of curve from Region 2 (quadratic region curve) and curve from Region 2 1/2.
In order to define the curve from Region 2 1/2, I applied that the slip percentage of 10% means that point C is at 90% of wGenRated, therefore being:
wGen_C = 0.9 * wGenRated = 0.9 * 1173.7 = 1056.33 rpm
And after calculating the cross point, the result is the following:
wGen_C = 1136.498 rpm
torque_C = 33035.165 Nm
Are these calculations alright?
Thank you in advance,
Looking forward for your answer,
Jon Martínez Rico